PermutationSymmetricTensors.jl

Provides a multidimensional array type that is symmetric under any permutation of its indices
Author IlianPihlajamaa
Popularity
3 Stars
Updated Last
4 Months Ago
Started In
May 2022

PermutationSymmetricTensors.jl

Build status (Github Actions) codecov.io

PermutationSymmetricTensors.jl provides an efficient framework for the use of multidimensional arrays that are symmetric under any permutation of their indices, implemented in pure Julia. Such symmetric tensors are implemented in the SymmetricTensor{T, N, dim} type, where T is the element type, dim is the number of indices required to index into the tensor, and N is the maximal index for each dimension. For example, to index a SymmetricTensor{ComplexF64, 20, 6}, you need 6 indices between 1 and 20. Note that we use the computer science definition of a tensor instead of the mathematical one: in the following, a tensor is just a multi-dimensional container of elements of some type T. As described above, we refer to the number of indices as the dimension of this tensor, because that is semantically consistent with the definition of a multidimensional array. In mathematics and physics texts, what we call dimension is usually referred to as the order, degree or rank of a tensor.

This package exports basic constructors of SymmetricTensors, and a few convenience functions for working with them. The main advantage of using a SymmetricTensor is that it requires much less memory to store than the full array would.

Construction

A SymmetricTensor can conveniently be constructed using zeros, ones, similar and rand.

julia> using PermutationSymmetricTensors

julia> a = rand(SymmetricTensor{Float64, 2, 3})
2×2×2 SymmetricTensor{Float64, 2, 3}:
[:, :, 1] =
 0.117155  0.815916
 0.815916  0.978778

[:, :, 2] =
 0.815916  0.978778
 0.978778  0.825148

julia> b = zeros(SymmetricTensor{ComplexF32, 3, 3})
3×3×3 SymmetricTensor{ComplexF32, 3, 3}:
[:, :, 1] =
 0.0+0.0im  0.0+0.0im  0.0+0.0im
 0.0+0.0im  0.0+0.0im  0.0+0.0im
 0.0+0.0im  0.0+0.0im  0.0+0.0im

[:, :, 2] =
 0.0+0.0im  0.0+0.0im  0.0+0.0im
 0.0+0.0im  0.0+0.0im  0.0+0.0im
 0.0+0.0im  0.0+0.0im  0.0+0.0im

[:, :, 3] =
 0.0+0.0im  0.0+0.0im  0.0+0.0im
 0.0+0.0im  0.0+0.0im  0.0+0.0im
 0.0+0.0im  0.0+0.0im  0.0+0.0im

julia>  c = ones(SymmetricTensor{Bool, 2, 2})
2×2 SymmetricTensor{Bool, 2, 2}:
 1  1
 1  1
 
julia> d = similar(c)
2×2 SymmetricTensor{Bool, 2, 2}:
 0  0
 0  0

julia> e = similar(d, Char)
2×2 SymmetricTensor{Char, 2, 2}:
 '\0'                '\x00\x00\x00\x01'
 '\x00\x00\x00\x01'  '\x00\x00\x00\x01'

Since the tensor is parametrized with its size, it is not necessary to provide any other arguments to zeros, ones, or rand. If the standard library Random is imported, rand!(a) will also work.

In order to create a SymmetricTensor from data stored in a Vector{T} directly, a constructor SymmetricTensor(data, Val(N), Val(dim)) can be called. It is important to make sure that the length of the given vector data agrees with the number of unique elements in the requested SymmetricTensor. The function find_symmetric_tensor_size(N, dim) is useful for that purpose. Given the number of elements in each dimension N and the number of dimensions dim, it returns the number of distinct elements that a SymmetricTensor{T, N, dim} needs to store.

julia> L = find_symmetric_tensor_size(3, 3)
10

julia> data = collect(1:L)
10-element Vector{Int64}:
  1
  2
  3
  4
  5
  6
  7
  8
  9
 10

julia> SymmetricTensor(data, Val(3), Val(3))
3×3×3 SymmetricTensor{Int64, 3, 3}:
[:, :, 1] =
 1  2  3
 2  4  5
 3  5  6

[:, :, 2] =
 2  4  5
 4  7  8
 5  8  9

[:, :, 3] =
 3  5   6
 5  8   9
 6  9  10

Note that SymmetricTensors leverage symmetry to minimize memory usage. It easy to create SymmetricTensors that would have more elements than typemax(Int64), if they had been stored naively.

julia> d = rand(SymmetricTensor{Float64, 14, 17});

julia> println("This tensor requires ", round(sizeof(d)/2^30, digits=2), "GB memory")
This tensor requires 0.89GB memory

julia> println("a full array of this shape would require ", length(d)*8/2^30, "GB memory.")
a full array of this shape would require 2.27e11GB memory.

julia> println("it would have ", 14^17, " elements.")
it would have -6402141418087907328 elements.

julia> println("oops, I meant ", big(14)^17)
oops, I meant 30491346729331195904

In the second line, the computation 14^17 overflowed, and therefore returned the wrong result. This is important to take this into account when calculating the sum of all elements of a SymmetricTensor{Int, N, dim}, if it is very large. To make iteration work on arrays for which N^dim > typemax(Int), length(d) returns an Int128 in those cases.

julia>  d = rand(SymmetricTensor{Float64, 15, 20});
julia> length(d)
332525673007965087890625
julia> typeof(ans)
Int128

julia> d = rand(SymmetricTensor{Float64, 15, 2});
julia> length(d)
225
julia> typeof(ans)
Int64

Standard use

The tensors can be indexed and mutated at will.

julia> a = rand(SymmetricTensor{Int8, 3, 3})
3×3×3 SymmetricTensor{Int8, 3, 3}:
[:, :, 1] =
 -115  -31  117
  -31  110   95
  117   95  -57

[:, :, 2] =
 -31  110    95
 110  -30    33
  95   33  -106

[:, :, 3] =
 117    95   -57
  95    33  -106
 -57  -106    87

julia> a[1,2,3]
95

julia> a[3,1,2]
95

julia> a[3,2,2] = 6
6

julia> a
3×3×3 SymmetricTensor{Int8, 3, 3}:
[:, :, 1] =
 -115  -31  117
  -31  110   95
  117   95  -57

[:, :, 2] =
 -31  110    95
 110  -30     6
  95    6  -106

[:, :, 3] =
 117    95   -57
  95     6  -106
 -57  -106    87

julia> a[:, 1, 1] .= 0
3-element view(::SymmetricTensor{Int8, 3, 3}, :, 1, 1) with eltype Int8:
 0
 0
 0

julia> a
3×3×3 SymmetricTensor{Int8, 3, 3}:
[:, :, 1] =
 0    0    0
 0  110   95
 0   95  -57

[:, :, 2] =
   0  110    95
 110  -30     6
  95    6  -106

[:, :, 3] =
   0    95   -57
  95     6  -106
 -57  -106    87

As, you can see, mutating one element also mutates all elements that are equivalent under index permutation.

They can also be iterated over and support most operations that arbitrary AbstractArrays do.

julia> a = rand(SymmetricTensor{BigFloat, 2, 4});

julia> for (i,ai) in enumerate(a)
           println((; i, ai))
       end
(i = 1, ai = 0.2504089172066270587643679267492732606636747737542205201257084506876941174077477)
(i = 2, ai = 0.1860567927479512764579583273597475579165054085072190505299583862788352760987293)
(i = 3, ai = 0.1860567927479512764579583273597475579165054085072190505299583862788352760987293)
(i = 4, ai = 0.4835838555693179868982759692607130469187769066045701314885210270407212019687799)
(i = 5, ai = 0.1860567927479512764579583273597475579165054085072190505299583862788352760987293)
(i = 6, ai = 0.4835838555693179868982759692607130469187769066045701314885210270407212019687799)
(i = 7, ai = 0.4835838555693179868982759692607130469187769066045701314885210270407212019687799)
(i = 8, ai = 0.3477955309561294416780053339785331891151633045252627608308216556228621260564572)
(i = 9, ai = 0.1860567927479512764579583273597475579165054085072190505299583862788352760987293)
(i = 10, ai = 0.4835838555693179868982759692607130469187769066045701314885210270407212019687799)
(i = 11, ai = 0.4835838555693179868982759692607130469187769066045701314885210270407212019687799)
(i = 12, ai = 0.3477955309561294416780053339785331891151633045252627608308216556228621260564572)
(i = 13, ai = 0.4835838555693179868982759692607130469187769066045701314885210270407212019687799)
(i = 14, ai = 0.3477955309561294416780053339785331891151633045252627608308216556228621260564572)
(i = 15, ai = 0.3477955309561294416780053339785331891151633045252627608308216556228621260564572)
(i = 16, ai = 0.6260418198971816214133682349248890223510908167601655542512797867183309913317024)

julia> size(a)
(2, 2, 2, 2)

julia> ndims(a)
4

julia> axes(a)
(Base.OneTo(2), Base.OneTo(2), Base.OneTo(2), Base.OneTo(2))

julia> length(a)
16

julia> sum(a)
5.913363165336039474111246622591563552654101882271734108751234567257141929172806

julia> prod(a)
3.515296863282957514709371560171304793858187682416751663789389978162540592035332e-08

julia> extrema(a)
(0.1860567927479512764579583273597475579165054085072190505299583862788352760987293, 0.6260418198971816214133682349248890223510908167601655542512797867183309913317024)

julia> lastindex(a)
16

julia> [i for i in eachindex(a)]
2×2×2×2 Array{CartesianIndex{4}, 4}:
[:, :, 1, 1] =
 CartesianIndex(1, 1, 1, 1)  CartesianIndex(1, 2, 1, 1)
 CartesianIndex(2, 1, 1, 1)  CartesianIndex(2, 2, 1, 1)

[:, :, 2, 1] =
 CartesianIndex(1, 1, 2, 1)  CartesianIndex(1, 2, 2, 1)
 CartesianIndex(2, 1, 2, 1)  CartesianIndex(2, 2, 2, 1)

[:, :, 1, 2] =
 CartesianIndex(1, 1, 1, 2)  CartesianIndex(1, 2, 1, 2)
 CartesianIndex(2, 1, 1, 2)  CartesianIndex(2, 2, 1, 2)

[:, :, 2, 2] =
 CartesianIndex(1, 1, 2, 2)  CartesianIndex(1, 2, 2, 2)
 CartesianIndex(2, 1, 2, 2)  CartesianIndex(2, 2, 2, 2)

However, the only functions from Base that are explicitly overloaded are zeros, ones, rand(!), similar, sizeof, size, length, getindex, and setindex!. All other operations shown above fall back to the implementations for AbstractArray of which SymmetricTensor is a subtype. Many therefore have highly suboptimal performance. More examples of that are given in the Performance section below.

Currently, broadcasting will always convert a SymmetricTensor into a full N-dimensional Array. For simple broadcasts, such as applying elementwise functions, instead consider broadcasting on the data-field, which holds all data that the symmetric tensor contains.

julia> @time a = rand(SymmetricTensor{Float64, 10, 8});
  0.000170 seconds (13 allocations: 191.266 KiB)

julia> @time b = a .* 0;
  2.755832 seconds (4 allocations: 762.940 MiB, 1.64% gc time)

julia> typeof(b)
Array{Float64, 8}

julia> @time c = similar(a);
  0.000125 seconds (13 allocations: 191.266 KiB)
  
julia> @time c.data .= a.data .* 0 .+ 1;
  0.000023 seconds (4 allocations: 128 bytes)
  
julia> sum(c) == length(c)
true

Be aware that some inplace operations can give unexpected results:

julia> a = rand(SymmetricTensor{Float64, 2, 2})
2×2 SymmetricTensor{Float64, 2, 2}:
 0.520987  0.84325
 0.84325   0.693854
 
julia> sort!(a, dims=2)
2×2 SymmetricTensor{Float64, 2, 2}:
 0.520987  0.693854
 0.693854  0.84325

Convenience Functions

find_full_indices(N, dim) or find_full_indices(a::SymmetricTensor) returns an ordered array of tuples of indices (i1, i2, i3, ..., i{dim}) such that i1 >= i2 >= i3 ... >= i{dim}. This can be used to find the cartesian index that corresponds the index of the underlying data vector of a SymmetricTensor{T, N, dim}. Example:

julia> find_full_indices(3, 3)
  10-element Vector{Tuple{Int32, Int32, Int32}}:
  (1, 1, 1)
  (2, 1, 1)
  (3, 1, 1)
  (2, 2, 1)
  (3, 2, 1)
  (3, 3, 1)
  (2, 2, 2)
  (3, 2, 2)
  (3, 3, 2)
  (3, 3, 3)
  
julia> a = rand(SymmetricTensor{Float64, 2, 8});

julia> full_indices = find_full_indices(a)
9-element Vector{NTuple{8, Int32}}:
 (1, 1, 1, 1, 1, 1, 1, 1)
 (2, 1, 1, 1, 1, 1, 1, 1)
 (2, 2, 1, 1, 1, 1, 1, 1)
 (2, 2, 2, 1, 1, 1, 1, 1)
 (2, 2, 2, 2, 1, 1, 1, 1)
 (2, 2, 2, 2, 2, 1, 1, 1)
 (2, 2, 2, 2, 2, 2, 1, 1)
 (2, 2, 2, 2, 2, 2, 2, 1)
 (2, 2, 2, 2, 2, 2, 2, 2)
 
 julia> a.data[4]
0.405316936154127

julia> indices = full_indices[4]
(2, 2, 2, 1, 1, 1, 1, 1)

julia> a[indices...]
0.405316936154127

find_degeneracy(N, dim) or find_degeneracy(a::SymmetricTensor) returns a SymmetricTensor{Int64, N, dim} of which each element specifies the number of index permutations that point to the same element. Examples:

  julia> find_degeneracy(3, 3)
  3×3×3 SymmetricTensor{Int64, 3, 3}:
  [:, :, 1] =
  1  3  3
  3  3  6
  3  6  3

  [:, :, 2] =
  3  3  6
  3  1  3
  6  3  3

  [:, :, 3] =
  3  6  3
  6  3  3
  3  3  1

  julia> a = rand(SymmetricTensor{Float64, 2,4});

  julia> find_degeneracy(a)
  2×2×2×2 SymmetricTensor{Int64, 2, 4}:
  [:, :, 1, 1] =
  1  4
  4  6

  [:, :, 2, 1] =
  4  6
  6  4

  [:, :, 1, 2] =
  4  6
  6  4

  [:, :, 2, 2] =
  6  4
  4  1

Performance

SymmetricTensors should be used mainly to save memory as explained above. In exchange, they sacrifice the performance of indexing. However, as we shall see, also many basic operations on symmetric tensors outperform those applied to full arrays, if their dimensionality is sufficiently large.

Creation and indexing:

using BenchmarkTools

julia> N = 100;  dim = 2;

julia> a = @btime zeros(ntuple(x->N,dim));
  2.571 μs (2 allocations: 78.17 KiB)

julia> b = @btime zeros(SymmetricTensor{Float64, $N, $dim});
  6.250 μs (7 allocations: 41.45 KiB)

julia> @btime $a[53, 23]
  1.900 ns (0 allocations: 0 bytes)
0.0

julia> @btime $b[53, 23]
  2.200 ns (0 allocations: 0 bytes)
0.0


julia> N = 100;  dim = 4;

julia> a = @btime zeros(ntuple(x->$N, $dim));
  93.489 ms (4 allocations: 762.94 MiB)

julia> b = @btime zeros(SymmetricTensor{Float64, $N, $dim});
  4.803 ms (9 allocations: 33.74 MiB)

julia> @btime $a[53, 23, 23, 12]
  1.900 ns (0 allocations: 0 bytes)
0.0

julia> @btime $b[53, 23, 23, 12]
  3.300 ns (0 allocations: 0 bytes)
0.0


julia> N = 10;  dim = 9;

julia> a = @btime zeros(ntuple(x->$N, $dim));
  883.687 ms (4 allocations: 7.45 GiB)

julia> b = @btime zeros(SymmetricTensor{Float64, $N, $dim});
  170.900 μs (15 allocations: 381.67 KiB)

julia> @btime $a[5,2,6,8,5,3,4,5,7]
  4.400 ns (0 allocations: 0 bytes)
0.0

julia> @btime $b[5,2,6,8,5,3,4,5,7]
  32.864 ns (0 allocations: 0 bytes)
0.0

Even though indexing into a SymmetricTensor is slower than it is into a standard Array, by abusing the symmetry of the underlying data, many basic operations can be made very efficient by applying them to the data field of the tensor directly, instead of on the tensor itself.

Example:

julia> N = 5;  dim = 9;

julia> a = rand(SymmetricTensor{Float64, N, dim});

julia> b = a .* 1; # full array

julia> @btime extrema($a)
  72.330 ms (0 allocations: 0 bytes)
(0.0011042800114182683, 0.9971024600776325)

julia> @btime extrema($b)
  3.807 ms (0 allocations: 0 bytes)
(0.0011042800114182683, 0.9971024600776325)

julia> @btime extrema($a.data)
  1.600 μs (0 allocations: 0 bytes)
(0.0011042800114182683, 0.9971024600776325)

In the example above, by calling extrema on the data field, we avoided looping over the vast majority of the elements.

The auxiliary functions find_degeneracy and find_full_indices are sometimes useful for implementing efficient computations on a SymmetricTensor.

Example 1: find the index of the smallest element in a SymmetricTensor

julia> N = 5;  dim = 9;

julia> a = rand(SymmetricTensor{Float64, N, dim});

julia> b = a .* 1; # full array

julia> @btime findmin($a)
  78.533 ms (0 allocations: 0 bytes)
(0.0011042800114182683, CartesianIndex(5, 5, 5, 3, 3, 3, 3, 3, 3))

julia> @btime findmin($b)
  14.663 ms (0 allocations: 0 bytes)
(0.0011042800114182683, CartesianIndex(5, 5, 5, 3, 3, 3, 3, 3, 3))

julia> full_indices = @btime find_full_indices(a);
  10.500 μs (6 allocations: 97.00 KiB)

julia> @btime findmin($a.data)
  1.180 μs (0 allocations: 0 bytes)
(0.0011042800114182683, 670)

julia> full_indices[670]
(5, 5, 5, 3, 3, 3, 3, 3, 3)

Example 2: sum of a SymmetricTensor

julia> a = rand(SymmetricTensor{Float64, 10, 8});

julia> b = a .* 1; # full array

julia> @btime sum($a)
  2.342 s (0 allocations: 0 bytes)
5.022884033216443e7

julia> @btime sum($b)
  25.777 ms (0 allocations: 0 bytes)
5.022884033248687e7

julia> degeneracy = @btime find_degeneracy($a);
  7.892 ms (193871 allocations: 4.42 MiB)

julia> @btime sum($a.data .* $degeneracy.data) # would be even more efficient with LinearAlgebra.dot...
  13.900 μs (2 allocations: 189.98 KiB)
5.022884033248686e7

Since full_indices and degeneracy depend only on the shape of a, they can often be precomputed for better performance.

Implementation

An instance a of a SymmetricTensor{T, N, dim} contains two fields.

  • a.data is a Vector{T} that stores all the elements of the symmetric tensor. Its length is given by L = binomial(N-1+dim, dim), or more conveniently L = find_symmetric_tensor_size(N, dim).
  • a.linear_indices is a Vector{Vector{Int64}} that is needed when a is indexed. The outer vector has length length(a.linear_indices) equal to dim. The length of the elements of that vector are equal to N. To index a SymmetricTensor{Float64, 50, 3} at indices I = (21, 45, 21), first the indices are sorted in descending order. Then, the linear index is found by evaluating index = (A.linear_indices[1])[45] + (A.linear_indices[2])[21] + (A.linear_indices[3])[21]. This linear index can now be used to get the value: val = a.data[index].

Many methods for operating with SymmetricTensors are implemented using generated functions to provide efficient implementations based on their size.

See also

There are two packages with comparable functionality, SymmetricTensors.jl and Tensors.jl.

Tensors.jl provides immutable, stack-allocated 1-, 2-, and 4-dimensional symmetric tensors. This package is preferable if the tensors are small, that is, when they have fewer than roughly 100 elements. It is also more full-featured, implementing many different operations on the tensors instead of just the basic functionality.

SymmetricTensors.jl provides a SymmetricTensor type just like the one exported in this package. Its implementation is based on a blocked memory pattern, sacrificing performance for cache locality. Some benchmarks:

import SymmetricTensors
using BenchmarkTools

Tensor creation:

julia> T = Float64;
julia> N = 30;
julia> dim = 5;

julia> a  = @btime rand(SymmetricTensors.SymmetricTensor{$T, $dim}, $N);
  2.601 s (21697571 allocations: 1.00 GiB)

julia> sizeof(a.frame)
6075000

julia> b  = @btime rand(PermutationSymmetricTensors.SymmetricTensor{$T, $N, $dim});
  642.400 μs (10 allocations: 2.12 MiB)

julia> sizeof(b)
2227288

getindex and setindex!:

julia> @btime $a[1,5,2,5,21];
  2.189 μs (24 allocations: 1.38 KiB)

julia> @btime $a[1,5,2,5,21] = 6.0;
  50.800 μs (767 allocations: 51.06 KiB)

julia> @btime $b[1,5,2,5,21];
  4.200 ns (0 allocations: 0 bytes)

julia> @btime $b[1,5,2,5,21] = 6.0;
  4.500 ns (0 allocations: 0 bytes)

Used By Packages

No packages found.