Because NaN is just missing with hardware support!
Fast summary statistics, histograms, and binning — all ignoring NaNs, as if NaN represented missing data.
See also JuliaSIMD/VectorizedStatistics.jl for similar vectorized implementations that don't ignore NaNs.
Summary statistics exported by NaNStatistics are generally named the same as their normal counterparts, but with "nan" in front of the name, similar to the Matlab and NumPy conventions. Options include:
nansumnanminimumnanmaximumnanextrema
nanmeanarithmetic mean, ignoringNaNsnanmedianmedian, ignoringNaNsnanmedian!asnanmedianbut quicksorts in-place for efficiency
nanvarvariancenanstdstandard deviationnancovcovariancenancorPearson's product-moment correlationnanaadmean (average) absolute deviation from the meannanmadmedian absolute deviation from the mediannanmad!asnanmadbut quicksorts in-place for efficiencynanrangerange between nanmaximum and nanminimumnanpctilepercentilenanpctile!asnanpctilebut quicksorts in-place for efficiency
nanskewnessskewnessnankurtosisexcess kurtosis
Note that, regardless of implementation, functions involving medians or percentiles are generally significantly slower than other summary statistics, since calculating a median or percentile requires a quicksort or quickselect of the input array; if not done in-place as in nanmedian! and nanpctile! then a copy of the entire array must also be made.
These functions will generally support the same dims keyword argument as their normal Julia counterparts (though are most efficient when operating on an entire collection).
As an alternative to dims, the dim keyword is also supported, which behaves identially to dims except that it also (as is the norm in some other languages) drops any singleton dimensions that have been reduced over.
julia> a = rand(100000);
julia> minimum(a)
9.70221275542471e-7
julia> using NaNStatistics
julia> nanminimum(a)
9.70221275542471e-7
julia> a[rand(1:100000, 10000)] .= NaN;
julia> nanminimum(a)
7.630517166790085e-6
The main 1D and 2D histogram function is histcounts (with an in-place variant histcounts!), and will, as you might expect for this package, ignore NaNs. However, it might be worth using for speed even if your data don't contain any NaNs:
julia> b = 10 * rand(100000);
julia> using StatsBase
julia> @btime fit(Histogram, $b, 0:1:10, closed=:right)
526.750 μs (2 allocations: 208 bytes)
Histogram{Int64, 1, Tuple{StepRange{Int64, Int64}}}
edges:
0:1:10
weights: [10042, 10105, 9976, 9980, 10073, 10038, 9983, 9802, 10056, 9945]
closed: right
isdensity: false
julia> using NaNStatistics
julia> @btime histcounts($b, 0:1:10)
155.083 μs (2 allocations: 176 bytes)
10-element Vector{Int64}:
10042
10105
9976
9980
10073
10038
9983
9802
10056
9945
(Timings as of Julia v1.10.4, NaNStatistics v0.6.36, Apple M1 Max)
In addition, several functions are provided to estimate the summary statistics of a dataset from its histogram, specifically
histmeanarithmetic meanhistvarvariancehiststdstandard deviationhistskewnessskewnesshistkurtosisexcess kurtosis
NaNStatistics also provides functions that will efficiently calculate the summary statistics of a given dependent variable y binned by an independent variable x. These currently include:
nanbinmean/nanbinmean!nanbinmedian/nanbinmedian!
julia> x = 10 * rand(100000);
julia> y = x.^2 .+ randn.();
julia> xmin, xmax, nbins = 0, 10, 10;
julia> @btime nanbinmean($x,$y,xmin,xmax,nbins)
222.542 μs (2 allocations: 288 bytes)
10-element Vector{Float64}:
0.3482167982440996
2.32463720126215
6.348942343257478
12.352990978599395
20.34955219534221
30.31123519946431
42.3578375163112
56.33841854482159
72.23884588251572
90.30275863080671
movmeanA simple moving average function, which can operate in 1D or 2D, ignoring NaNs.
julia> A = rand(1:10, 4,4)
4×4 Matrix{Int64}:
3 5 10 3
4 2 5 8
5 6 8 8
2 6 10 6
julia> movmean(A, 3)
4×4 Matrix{Float64}:
3.5 4.83333 5.5 6.5
4.16667 5.33333 6.11111 7.0
4.16667 5.33333 6.55556 7.5
4.75 6.16667 7.33333 8.0
nanstandardize/nanstandardize!De-mean and set to unit variance